SEBI Online Test in English Series 1, SEBI Online Mock Test 1
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SEBI Online Test in English Series 1, SEBI Online Mock Test 1, SEBI Free Online Test Series 1. RRB Exam Online Test 2024, SEBI Free Mock Test Exam 2024. SEBI Exam Free Online Quiz 2024, SEBI Full Online Mock Test Series 1st in English. RRB Online Test for All Subjects, SEBI Free Mock Test Series in English. SEBI Free Mock Test Series 1. SEBI English Language Online Test in English Series 1st. SEBI Quantitative Aptitude Quiz 2024, SEBI Reasoning Ability Free Online Test. Take SEBI Online Quiz. The SEBI Full online mock test paper is free for all students. SEBI Question and Answers in English and Hindi Series 1. Here we are providing SEBI Full Mock Test Paper in English. SEBI Mock Test Series 1st 2024. Now Test your self for SEBI Exam by using below quiz…
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Question 1 of 50
1. Question
The area of sector of a circle whose radius is 12 metro and whose angle at the center is 42° is?
Correct
42/360 * 22/7 * 12 * 12 = 52.8 m2
Incorrect
42/360 * 22/7 * 12 * 12 = 52.8 m2
-
Question 2 of 50
2. Question
Find the one which does not belong to that group ?
Correct
48, 75, 84 and 57 are divisible by 3 but not 35.
Incorrect
48, 75, 84 and 57 are divisible by 3 but not 35.
-
Question 3 of 50
3. Question
A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Correct
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.Incorrect
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways. -
Question 4 of 50
4. Question
Find the least number when successively divided by 2, 3 and 7 leaves remainders 1, 2 and 3 respectively?
Correct
2) 65 (32 3) 32 (10 7) 10 (1
64 30 7
——– ——– – —–
1 2 3
=> 65Incorrect
2) 65 (32 3) 32 (10 7) 10 (1
64 30 7
——– ——– – —–
1 2 3
=> 65 -
Question 5 of 50
5. Question
The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?
Correct
4a = 68 => a = 17
172 – 82 = 152
1/2 * 16 * 30 = 240Incorrect
4a = 68 => a = 17
172 – 82 = 152
1/2 * 16 * 30 = 240 -
Question 6 of 50
6. Question
The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?
Correct
5000 = 72(100/R)2
5 R2 = 720 => R = 12Incorrect
5000 = 72(100/R)2
5 R2 = 720 => R = 12 -
Question 7 of 50
7. Question
The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Correct
Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 28/2 = 35 cm2Incorrect
Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 28/2 = 35 cm2 -
Question 8 of 50
8. Question
In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
Correct
(4000*3*R)/100 = (5000*5*4)/100
R = 8 1/3Incorrect
(4000*3*R)/100 = (5000*5*4)/100
R = 8 1/3 -
Question 9 of 50
9. Question
How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
Correct
20000(11/10)4 – 20000(6/5)2 = 482
Incorrect
20000(11/10)4 – 20000(6/5)2 = 482
-
Question 10 of 50
10. Question
Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?
Correct
Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5Incorrect
Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5 -
Question 11 of 50
11. Question
26.98% of 6002 + 45.01% of 4199 = ?
Correct
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500Incorrect
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500 -
Question 12 of 50
12. Question
Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
Correct
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr.Incorrect
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr. -
Question 13 of 50
13. Question
A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
Correct
US = 25
DS = 35
M = (35 – 25)/2 = 5Incorrect
US = 25
DS = 35
M = (35 – 25)/2 = 5 -
Question 14 of 50
14. Question
Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.15 per cubic meter?
Correct
22/7 * 14 * 3/2 * 3/2 = 99 m2
99 * 15 = 1485Incorrect
22/7 * 14 * 3/2 * 3/2 = 99 m2
99 * 15 = 1485 -
Question 15 of 50
15. Question
(743.30)2 = ?
Correct
(743.30)2 = 552500
Incorrect
(743.30)2 = 552500
-
Question 16 of 50
16. Question
Three seventh of a number is 12 more than 40% of that number. What will be the 60% of that number?
Correct
3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 60/100 = 252/2 = 126Incorrect
3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 60/100 = 252/2 = 126 -
Question 17 of 50
17. Question
I. a2 + 11a + 30 = 0,
II. b2 + 6b + 5 = 0 to solve both the equations to find the values of a and b?Correct
I. (a + 6)(a + 5) = 0
=> a = -6, -5
II. (b + 5)(b + 1) = 0
=> b = -5, -1 => a ≤ bIncorrect
I. (a + 6)(a + 5) = 0
=> a = -6, -5
II. (b + 5)(b + 1) = 0
=> b = -5, -1 => a ≤ b -
Question 18 of 50
18. Question
Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
Correct
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6Incorrect
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6 -
Question 19 of 50
19. Question
The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Correct
Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X – 48 = 180
1000/x – 48 * 5/18 = 180
50 = 9X – 120
X = 68 KmphIncorrect
Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X – 48 = 180
1000/x – 48 * 5/18 = 180
50 = 9X – 120
X = 68 Kmph -
Question 20 of 50
20. Question
The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Correct
20 + 24 + 8 * 2 = 60/2 = 30
Incorrect
20 + 24 + 8 * 2 = 60/2 = 30
-
Question 21 of 50
21. Question
The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
Correct
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5Incorrect
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5 -
Question 22 of 50
22. Question
Rs. 1300 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4?
Correct
1/2:1/3:1/4 = 6:4:3
3/13*1300 = 300Incorrect
1/2:1/3:1/4 = 6:4:3
3/13*1300 = 300 -
Question 23 of 50
23. Question
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same sum at the rate and for the same time?
Correct
Sum = (50 * 100) / (2 * 5) = Rs. 500
Amount = [500 * (1 + 5/100)2] = Rs. 551.25
C.I. = (551.25 – 500) = Rs. 51.25.Incorrect
Sum = (50 * 100) / (2 * 5) = Rs. 500
Amount = [500 * (1 + 5/100)2] = Rs. 551.25
C.I. = (551.25 – 500) = Rs. 51.25. -
Question 24 of 50
24. Question
(562 – 242) * 1/32 + ?% of 1200 = 146
Correct
(562 – 242) * 1/32 + ?% of 1200 = 146
=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146
=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80
=> ? = 66/12 => 5 1/2Incorrect
(562 – 242) * 1/32 + ?% of 1200 = 146
=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146
=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80
=> ? = 66/12 => 5 1/2 -
Question 25 of 50
25. Question
The ratio of the present ages of Giri and Hari is 5 : 8. 12 years hence, the ratio of their ages will be 11 : 14. Find the difference in their present ages?
Correct
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x – 5x = 3x = 6 years.Incorrect
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x – 5x = 3x = 6 years. -
Question 26 of 50
26. Question
The curved surface of a sphere is 64 π cm2. Find its radius?
Correct
4 πr2 = 64 => r = 4
Incorrect
4 πr2 = 64 => r = 4
-
Question 27 of 50
27. Question
The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
Correct
A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 132D = 10
D = 5Incorrect
A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 132D = 10
D = 5 -
Question 28 of 50
28. Question
If 20% of a number, then 120% of that number will be?
Correct
Let the number x. Then,
20% of x = 120
x = (120 * 100)/20 = 600
120% of x = (120/100 * 600) = 720.Incorrect
Let the number x. Then,
20% of x = 120
x = (120 * 100)/20 = 600
120% of x = (120/100 * 600) = 720. -
Question 29 of 50
29. Question
If x = √8 – √7, y = √6 – √5 and z = √10 – 3, which of the following is true?
Correct
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 - √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y.Incorrect
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 - √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y. -
Question 30 of 50
30. Question
Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is:
Correct
Let the numbers be 3x, 4x and 5x.
Then, their L.C.M = 60x. So, 60x = 2400 or x = 40.
The numbers are (3 * 40), (4 * 40) and (5 * 40).
Hence, required H.C.F = 40.Incorrect
Let the numbers be 3x, 4x and 5x.
Then, their L.C.M = 60x. So, 60x = 2400 or x = 40.
The numbers are (3 * 40), (4 * 40) and (5 * 40).
Hence, required H.C.F = 40. -
Question 31 of 50
31. Question
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = ?
Correct
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28Incorrect
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28 -
Question 32 of 50
32. Question
If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?
Correct
a/d = (3/4)*(7/9)*(5/7) => 5/12
Incorrect
a/d = (3/4)*(7/9)*(5/7) => 5/12
-
Question 33 of 50
33. Question
A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?
Correct
Since S # 1/t
S1 : S2 = 1/t1 : 1/t2 = 1/8 : 1/6 = 3 : 4Incorrect
Since S # 1/t
S1 : S2 = 1/t1 : 1/t2 = 1/8 : 1/6 = 3 : 4 -
Question 34 of 50
34. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 daysIncorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days -
Question 35 of 50
35. Question
A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
Correct
25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000Incorrect
25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000 -
Question 36 of 50
36. Question
By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is:
Correct
Marked price = Rs. 300
C.P. = 100/120 * 300 = Rs. 250
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 20/250 * 100 = 8%.Incorrect
Marked price = Rs. 300
C.P. = 100/120 * 300 = Rs. 250
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 20/250 * 100 = 8%. -
Question 37 of 50
37. Question
12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work?
Correct
1 man’s 1 day work = 1/108
12 men’s 6 day’s work = 1/9 * 6 = 2/3
Remaining work = 1 – 2/3 = 1/3
18 men’s 1 day work = 1/108 * 18 = 1/6
1/6 work is done by them in 1 day.
1/3 work is done by them in 6 * 1/3 = 2 days.Incorrect
1 man’s 1 day work = 1/108
12 men’s 6 day’s work = 1/9 * 6 = 2/3
Remaining work = 1 – 2/3 = 1/3
18 men’s 1 day work = 1/108 * 18 = 1/6
1/6 work is done by them in 1 day.
1/3 work is done by them in 6 * 1/3 = 2 days. -
Question 38 of 50
38. Question
A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 16 cm. What is the length of the wire?
Correct
Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)2 * h = (4/3)π (12)3 => h = 9 cmIncorrect
Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)2 * h = (4/3)π (12)3 => h = 9 cm -
Question 39 of 50
39. Question
Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak’s share is:
Correct
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400.Incorrect
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400. -
Question 40 of 50
40. Question
The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is?
Correct
P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years.Incorrect
P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years. -
Question 41 of 50
41. Question
If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Correct
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm2Incorrect
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm2 -
Question 42 of 50
42. Question
A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
Correct
3/12 + (3 + x)/16 = 1
x = 9 daysIncorrect
3/12 + (3 + x)/16 = 1
x = 9 days -
Question 43 of 50
43. Question
(0.9 * 0.9 – 0.8 * 0.8)/1.7 = ?
Correct
As numerator is of the form a2 – b2 = (a + b) (a – b), so the given expression simplifying becomes
(0.92 – 0.82)/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1Incorrect
As numerator is of the form a2 – b2 = (a + b) (a – b), so the given expression simplifying becomes
(0.92 – 0.82)/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1 -
Question 44 of 50
44. Question
At what rate percent of simple interest will a sum of money double itself in 12 years?
Correct
Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)
= 25/3 = 8 1/3 %Incorrect
Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)
= 25/3 = 8 1/3 % -
Question 45 of 50
45. Question
The perimeter of a semi circle is 144 cm then the radius is?
Correct
Incorrect
-
Question 46 of 50
46. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 -
Question 47 of 50
47. Question
A bag contains a total of 93 coins in the form of one rupee and 50 paise coins. If the total value of coins in the bag is Rs.56, find the number of 50 paise coins in the bag?
Correct
Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74Incorrect
Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74 -
Question 48 of 50
48. Question
How many minimum number’s of whole square slabs are required for paving the floor 12.96 meters long and 3.84 meters side?
Correct
HCF of 384, 1296 = 48
48 * 48 * x = 384 * 1296
x = 216Incorrect
HCF of 384, 1296 = 48
48 * 48 * x = 384 * 1296
x = 216 -
Question 49 of 50
49. Question
21345 * 45 = 4270 * ?
Correct
? = (21345 * 45) / 4270
? = 225Incorrect
? = (21345 * 45) / 4270
? = 225 -
Question 50 of 50
50. Question
What is the sum of the local values of the digits 2, 3, 4, 5 in the number 2345?
Correct
2000 + 300 + 40 + 5 = 2345
Incorrect
2000 + 300 + 40 + 5 = 2345