IPPB Pre Quiz Series 4, IPPB Pre Online Test Series 4th, IPPB Mock Test
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IPPB Pre Quiz Series 4, IPPB Pre online test series 4th, IPPB mock test. RRB Exam Online Test 2024, IPPB Prelims Free Mock Test Exam 2024. IPPB Prelims Exam Free Online Quiz 2024, IPPB Prelims Full Online Mock Test Series 4th in English. RRB Online Test for All Subjects, IPPB Prelims Free Mock Test Series in English. IPPB Prelims Free Mock Test Series 4. IPPB Prelims English Language Online Test in English Series 4th. IPPB Prelims Quantitative Aptitude Quiz 2024, IPPB Prelims Reasoning Ability Free Online Test. Take IPPB Prelims Online Quiz. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi Series 4. Here we are providing IPPB Prelims Full Mock Test Paper in English. IPPB Prelims Mock Test Series 4th 2024. Now Test your self for IPPB Prelims Exam by using below quiz…
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Question 1 of 50
1. Question
A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
Correct
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023Incorrect
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023 
Question 2 of 50
2. Question
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Correct
Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 mIncorrect
Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m 
Question 3 of 50
3. Question
What is the least number, which is perfect square but contains 2700 as its factor?
Correct
900 * 3 * 3 = 8100
Incorrect
900 * 3 * 3 = 8100

Question 4 of 50
4. Question
Find the one which does not belong to that group ?
Correct
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.
Incorrect
Crocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

Question 5 of 50
5. Question
Simplify the following:
(169/121)^{3/2} * 27/2 * (13/22)^{1}Correct
(169/121)^{3/2} * 27/2 * (13/22)^{1}
(13^{2}/11^{2})^{3/2} * 27/2 * 22/13 = 13^{3}/11^{3} * 27/2 * 22/13
= 13^{4} 11^{4} 3^{3}Incorrect
(169/121)^{3/2} * 27/2 * (13/22)^{1}
(13^{2}/11^{2})^{3/2} * 27/2 * 22/13 = 13^{3}/11^{3} * 27/2 * 22/13
= 13^{4} 11^{4} 3^{3} 
Question 6 of 50
6. Question
40 is subtracted from 60% of a number, the result is 50. Find the number?
Correct
(60/100) * X – 40 = 50
6X = 900
X = 150Incorrect
(60/100) * X – 40 = 50
6X = 900
X = 150 
Question 7 of 50
7. Question
Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
Correct
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 = 36 km/hr.Incorrect
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 = 36 km/hr. 
Question 8 of 50
8. Question
50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?
Correct
After 5 days, the following situation prevails.
50 men can complete the work in 60 days.
30 men can complete the work in ? days.
M_{1} D_{1} = M_{2} D_{2}
=> 50 * 60 = 30 * D_{2}
=> D_{2} = (50 * 60)/30 = 100 days.Incorrect
After 5 days, the following situation prevails.
50 men can complete the work in 60 days.
30 men can complete the work in ? days.
M_{1} D_{1} = M_{2} D_{2}
=> 50 * 60 = 30 * D_{2}
=> D_{2} = (50 * 60)/30 = 100 days. 
Question 9 of 50
9. Question
The least square number which divides 8, 12 and 18 is?
Correct
LCM = 72
72 * 2 = 144Incorrect
LCM = 72
72 * 2 = 144 
Question 10 of 50
10. Question
How much time will take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Correct
Time = (100 * 81) / (450 * 4.5) = 4 years
Incorrect
Time = (100 * 81) / (450 * 4.5) = 4 years

Question 11 of 50
11. Question
A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.675 in all. Find the share of B?
Correct
A+B+C = 675
A = 3B
3B+B+B25 = 675
5B = 700
B = 140Incorrect
A+B+C = 675
A = 3B
3B+B+B25 = 675
5B = 700
B = 140 
Question 12 of 50
12. Question
Twenty four men can do a work in 35 days. How many men are required to complete the work in 21 days?
Correct
We have M_{1} D_{1} = M_{2} D_{2}
So, 24 * 35 = M_{2} * 21 => M_{2} = 40.Incorrect
We have M_{1} D_{1} = M_{2} D_{2}
So, 24 * 35 = M_{2} * 21 => M_{2} = 40. 
Question 13 of 50
13. Question
A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
Correct
π (23^{2} – 12^{2}) = 1210
Incorrect
π (23^{2} – 12^{2}) = 1210

Question 14 of 50
14. Question
A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
Correct
S = 240/16 * 18/5 = 54 kmph
Incorrect
S = 240/16 * 18/5 = 54 kmph

Question 15 of 50
15. Question
A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
Correct
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.Incorrect
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days. 
Question 16 of 50
16. Question
Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m.?
Correct
Let the distance traveled be x km.
Then, x/10 – x/15 = 2
3x – 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.
Learn more problems on : Time and DistanceIncorrect
Let the distance traveled be x km.
Then, x/10 – x/15 = 2
3x – 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.
Learn more problems on : Time and Distance 
Question 17 of 50
17. Question
A number when divided by 221 gives a remainder 43, what remainder will be obtained by dividing the same number 17?
Correct
221 + 43 = 264/17 = 9 (Remainder)
Incorrect
221 + 43 = 264/17 = 9 (Remainder)

Question 18 of 50
18. Question
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
Correct
160 = (180*4*R)/100
R = 5%Incorrect
160 = (180*4*R)/100
R = 5% 
Question 19 of 50
19. Question
Three number are in the ratio 5:6:7. The sum of its largest and smallest numbers equals the sum of the third number and 48. Find the third number?
Correct
Let the numbers be 5x, 6x and 7x.
Largest number = 7x
Smallest number = 5x
Third number = 6x
7x + 5x = 6x + 48
6x = 48
Third number is: 48.Incorrect
Let the numbers be 5x, 6x and 7x.
Largest number = 7x
Smallest number = 5x
Third number = 6x
7x + 5x = 6x + 48
6x = 48
Third number is: 48. 
Question 20 of 50
20. Question
A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is:
Correct
Let the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.
125/100 * 120/100 * 118/100 * x = 3009/100
177/100 x = 3009/100 => x = 17Incorrect
Let the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.
125/100 * 120/100 * 118/100 * x = 3009/100
177/100 x = 3009/100 => x = 17 
Question 21 of 50
21. Question
Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
Correct
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6Incorrect
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6 
Question 22 of 50
22. Question
Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178?
Correct
Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.
=> (90%) of (110%) of x = Rs. 2178.
=> (90/100)(110/100)x = 2178
=> x = (2178 * 100)/(9 * 11)
=> x = Rs. 2200Incorrect
Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.
=> (90%) of (110%) of x = Rs. 2178.
=> (90/100)(110/100)x = 2178
=> x = (2178 * 100)/(9 * 11)
=> x = Rs. 2200 
Question 23 of 50
23. Question
Find the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1:2.
Correct
Incorrect

Question 24 of 50
24. Question
Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively?
Correct
420) 9999 (23
= 9660
= ———
= 339
9999 – 339 = 9660 – 6 = 9654Incorrect
420) 9999 (23
= 9660
= ———
= 339
9999 – 339 = 9660 – 6 = 9654 
Question 25 of 50
25. Question
If 70% of an equal to 40% of b, then ratio between a and b is?
Correct
70 a = 40 b
a: b = 4: 7Incorrect
70 a = 40 b
a: b = 4: 7 
Question 26 of 50
26. Question
184 * 216 – 81 + 119 / 0.7 = ?
Correct
184 * 216 – 81 + 119 / 0.7 = 184/216 – 81 + 170
Using the concept of digit roots we can say digit root of 180 = 1 + 8 + 4 = 13 = 1 + 3 = 4.
i.e. we keep adding the digits till we get the sum as a single digit number.
Digit root of 216 is 0
Digit root of 81 is 0.
Digit root of 170 is 1 + 7 + 0 = 8
Thus the digit root of the answer must be (4)(0) – 0 + 8 = 8.
(39439) digit root is 3 + 9 + 4 + 3 + 9 = 28 2 + 8 = 10 1 + 0 = 1.
Digit root is 1.
Similarly the digit root of 39394 is 1 digit root of 94934 is 2.
Where as the digit root of 33949 is 1. Thus none of them could be the answer, hence the answer is choice (5) or 184 * 216 – 81 + 170 = 39833.Incorrect
184 * 216 – 81 + 119 / 0.7 = 184/216 – 81 + 170
Using the concept of digit roots we can say digit root of 180 = 1 + 8 + 4 = 13 = 1 + 3 = 4.
i.e. we keep adding the digits till we get the sum as a single digit number.
Digit root of 216 is 0
Digit root of 81 is 0.
Digit root of 170 is 1 + 7 + 0 = 8
Thus the digit root of the answer must be (4)(0) – 0 + 8 = 8.
(39439) digit root is 3 + 9 + 4 + 3 + 9 = 28 2 + 8 = 10 1 + 0 = 1.
Digit root is 1.
Similarly the digit root of 39394 is 1 digit root of 94934 is 2.
Where as the digit root of 33949 is 1. Thus none of them could be the answer, hence the answer is choice (5) or 184 * 216 – 81 + 170 = 39833. 
Question 27 of 50
27. Question
The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is .
Correct
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆Incorrect
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆ 
Question 28 of 50
28. Question
A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
Correct
Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180mIncorrect
Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m 
Question 29 of 50
29. Question
2^{42} + 4^{20} + 16^{11} + 64^{7} equals
Correct
2^{42} + 2^{40} + 2^{44} + 2^{42}
= 2^{40}(2^{2} + 1 + 2^{4} + 2^{2})
= 2^{40} * 25 = 2^{40} * 5^{2}Incorrect
2^{42} + 2^{40} + 2^{44} + 2^{42}
= 2^{40}(2^{2} + 1 + 2^{4} + 2^{2})
= 2^{40} * 25 = 2^{40} * 5^{2} 
Question 30 of 50
30. Question
How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?
Correct
50/100 * x = 30 * 20 => x = 1200
Incorrect
50/100 * x = 30 * 20 => x = 1200

Question 31 of 50
31. Question
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
Correct
6300:4200:10500
3:2:5
3/10 * 12100 = 3630Incorrect
6300:4200:10500
3:2:5
3/10 * 12100 = 3630 
Question 32 of 50
32. Question
A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook?
Correct
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy
=>5(300/x) – 10x – 50 = 0 => 150 + x^{2} + 5x = 0
multiplying both sides by 1/10x
=> x^{2} + 15x – 10x – 150 = 0
=> x(x + 15) – 10(x + 15) = 0
=> x = 10 or 15
As x>0, x = 10.Incorrect
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy
=>5(300/x) – 10x – 50 = 0 => 150 + x^{2} + 5x = 0
multiplying both sides by 1/10x
=> x^{2} + 15x – 10x – 150 = 0
=> x(x + 15) – 10(x + 15) = 0
=> x = 10 or 15
As x>0, x = 10. 
Question 33 of 50
33. Question
A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
Correct
Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P3) Hence, 15(P30) + 64 = 16P => P = 19.Incorrect
Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P3) Hence, 15(P30) + 64 = 16P => P = 19. 
Question 34 of 50
34. Question
(a^{3} b^{2} / a^{2} b^{2})^{3} * (a^{3} b^{4} / a^{3} b^{3}) / (a^{2} b^{3}/a^{4} b^{3}) = ?
Correct
(a^{3} b^{2} / a^{2} b^{2})^{3} * (a^{3} b^{4} / a^{3} b^{3}) / (a^{2} b^{3}/a^{4} b^{3})
= (a^{5} b^{4})^{3} * a^{6}b^{7} / a^{2}b^{6}
= a^{15}b^{12} * a^{6}b^{7} * a^{2}b^{6}
= a^{19} b^{1}Incorrect
(a^{3} b^{2} / a^{2} b^{2})^{3} * (a^{3} b^{4} / a^{3} b^{3}) / (a^{2} b^{3}/a^{4} b^{3})
= (a^{5} b^{4})^{3} * a^{6}b^{7} / a^{2}b^{6}
= a^{15}b^{12} * a^{6}b^{7} * a^{2}b^{6}
= a^{19} b^{1} 
Question 35 of 50
35. Question
A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Correct
45*12 : 54*x = 2: 1
x = 5
12 5 = 7Incorrect
45*12 : 54*x = 2: 1
x = 5
12 5 = 7 
Question 36 of 50
36. Question
15% of 195 + 14% of 205 = ?
Correct
15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200
= 30 + 28 = 58Incorrect
15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200
= 30 + 28 = 58 
Question 37 of 50
37. Question
Find the one which does not belong to that group ?
Correct
Except Regiment, all others are caders of army officers.
Incorrect
Except Regiment, all others are caders of army officers.

Question 38 of 50
38. Question
The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square.
Correct
Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found.Incorrect
Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found. 
Question 39 of 50
39. Question
Find the number which multiplied by 15 is increased by 196.
Correct
Let the number be x. Then,
15x – x = 196
x = 14Incorrect
Let the number be x. Then,
15x – x = 196
x = 14 
Question 40 of 50
40. Question
Find the one which does not belong to that group ?
Correct
42624, 37573, 74347 and 93339 are palindromes but not 84284.
Incorrect
42624, 37573, 74347 and 93339 are palindromes but not 84284.

Question 41 of 50
41. Question
{20 – [7 – (3 2)] + 1/3 (4.2)} / 1.4 = ?
Correct
{20 – [7 – (3 2)] + 1/3 (4.2)} / 1.4
=> [20 – (7 – 1) + 1.4] / 1.4
=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11Incorrect
{20 – [7 – (3 2)] + 1/3 (4.2)} / 1.4
=> [20 – (7 – 1) + 1.4] / 1.4
=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11 
Question 42 of 50
42. Question
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
Correct
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6^{th} = 294 + 312 – 550 = 56Incorrect
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6^{th} = 294 + 312 – 550 = 56 
Question 43 of 50
43. Question
Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?
Correct
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000Incorrect
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000 
Question 44 of 50
44. Question
In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
Correct
Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
Incorrect
Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.

Question 45 of 50
45. Question
In a pair of fractions, fraction A is twice the fraction B and the product of two fractions is 2/25. What is the value of fraction A?
Correct
A = 2B => B = 1/2 A, so, AB = 2/25
1/2 A^{2} = 2/25
A^{2} = 4/25
A = 2/5Incorrect
A = 2B => B = 1/2 A, so, AB = 2/25
1/2 A^{2} = 2/25
A^{2} = 4/25
A = 2/5 
Question 46 of 50
46. Question
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?
Correct
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.Incorrect
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430. 
Question 47 of 50
47. Question
Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Correct
x + y = 80
x – 4y = 5
x = 65 y = 15Incorrect
x + y = 80
x – 4y = 5
x = 65 y = 15 
Question 48 of 50
48. Question
(0.9 * 0.9 – 0.8 * 0.8)/1.7 = ?
Correct
As numerator is of the form a^{2} – b^{2} = (a + b) (a – b), so the given expression simplifying becomes
(0.9^{2} – 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1Incorrect
As numerator is of the form a^{2} – b^{2} = (a + b) (a – b), so the given expression simplifying becomes
(0.9^{2} – 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1 
Question 49 of 50
49. Question
An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes?
Correct
Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5
S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25
So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 – 100) = 10.25%.Incorrect
Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5
S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25
So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 – 100) = 10.25%. 
Question 50 of 50
50. Question
The ratio of two numbers is 2:3 and the sum of their cubes is 945. The difference of number is?
Correct
2x 3x
8x cube + 27x cube = 945
35x cube = 945
x cube = 27 => x = 3Incorrect
2x 3x
8x cube + 27x cube = 945
35x cube = 945
x cube = 27 => x = 3