IPPB Mains Online Test Series 5, IPPB Test Series, IPPB Mock Test
Finish Quiz
0 of 50 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 16
 17
 18
 19
 20
 21
 22
 23
 24
 25
 26
 27
 28
 29
 30
 31
 32
 33
 34
 35
 36
 37
 38
 39
 40
 41
 42
 43
 44
 45
 46
 47
 48
 49
 50
Information
IPPB Mains Online Test Series 5, IPPB Test Series, IPPB Mock Test. RRB Exam Online Test 2024, IPPB Mains Free Mock Test Exam 2024. IPPB Mains Exam Free Online Quiz 2024, IPPB Mains Full Online Mock Test Series 5th in English. RRB Online Test for All Subjects, IPPB Mains Free Mock Test Series in English. IPPB Mains Free Mock Test Series 5. IPPB Mains English Language Online Test in English Series 5th. IPPB Mains Quantitative Aptitude Quiz 2024, IPPB Mains Reasoning Ability Free Online Test. Take IPPB Mains Online Quiz. The IPPB Mains Full online mock test paper is free for all students. IPPB Mains Question and Answers in English and Hindi Series 5. Here we are providing IPPB Mains Full Mock Test Paper in English. IPPB Mains Mock Test Series 5th 2024. Now Test your self for IPPB Mains Exam by using below quiz…
This paper has 50 questions.
Time allowed is 50 minutes.
The IPPB Mains Online Test Series 5th, IPPB Mains Free Online Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 50 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Average score 

Your score 

Categories
 Not categorized 0%
Pos.  Name  Entered on  Points  Result 

Table is loading  
No data available  
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 16
 17
 18
 19
 20
 21
 22
 23
 24
 25
 26
 27
 28
 29
 30
 31
 32
 33
 34
 35
 36
 37
 38
 39
 40
 41
 42
 43
 44
 45
 46
 47
 48
 49
 50
 Answered
 Review

Question 1 of 50
1. Question
Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?
Correct
S:E = 1:3
E:M = 3:5
————
S:E:M = 3:9:15
3/27 * 162 = 18Incorrect
S:E = 1:3
E:M = 3:5
————
S:E:M = 3:9:15
3/27 * 162 = 18 
Question 2 of 50
2. Question
From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is .
Correct
Let E_{1} be the event of drawing a red card.
Let E_{2} be the event of drawing a king .
P(E_{1} ∩ E_{2}) = P(E_{1}) . P(E_{2})
(As E_{1} and E_{2} are independent)
= 1/2 * 1/13 = 1/26Incorrect
Let E_{1} be the event of drawing a red card.
Let E_{2} be the event of drawing a king .
P(E_{1} ∩ E_{2}) = P(E_{1}) . P(E_{2})
(As E_{1} and E_{2} are independent)
= 1/2 * 1/13 = 1/26 
Question 3 of 50
3. Question
The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Correct
a^{2} = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999Incorrect
a^{2} = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999 
Question 4 of 50
4. Question
A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point?
Correct
L.C.M of 252, 308 and 198 = 2772
So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec.Incorrect
L.C.M of 252, 308 and 198 = 2772
So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec. 
Question 5 of 50
5. Question
There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?
Correct
760 — 22
760 — 20
x —– 19
x*19 = 760*20
x = 800
760
——
40Incorrect
760 — 22
760 — 20
x —– 19
x*19 = 760*20
x = 800
760
——
40 
Question 6 of 50
6. Question
If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then A:B:C:D is:
Correct
A:B = 2:3, B:C = 4:5 = (4 * 3/4):(5 * 3/4) = 3:15/4
and C:D = 6:7 = (6 * 15/24):(7 * 15/24) = 15/4:35/8 A:B:C:D = 2:3:15/4:35/8 = 16:24:30:35Incorrect
A:B = 2:3, B:C = 4:5 = (4 * 3/4):(5 * 3/4) = 3:15/4
and C:D = 6:7 = (6 * 15/24):(7 * 15/24) = 15/4:35/8 A:B:C:D = 2:3:15/4:35/8 = 16:24:30:35 
Question 7 of 50
7. Question
Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?
Correct
1/30 + 1/40 = 7/120
120/7 = 17 1/7 daysIncorrect
1/30 + 1/40 = 7/120
120/7 = 17 1/7 days 
Question 8 of 50
8. Question
The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
Correct
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm.Incorrect
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm. 
Question 9 of 50
9. Question
A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
Correct
100 — 100 — 10
100 — 10
——————–
300 — 20 yearsIncorrect
100 — 100 — 10
100 — 10
——————–
300 — 20 years 
Question 10 of 50
10. Question
Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
Correct
A = 8000(21/20)^{3} = 9261
Incorrect
A = 8000(21/20)^{3} = 9261

Question 11 of 50
11. Question
A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
Correct
WC of A: B = 1:2
B: C = 1:2
———————
A: B: C = 1:2:4Incorrect
WC of A: B = 1:2
B: C = 1:2
———————
A: B: C = 1:2:4 
Question 12 of 50
12. Question
If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
Correct
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 * 6/23 = Rs. 204.Incorrect
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 * 6/23 = Rs. 204. 
Question 13 of 50
13. Question
A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?
Correct
A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336 = 3:4:7Incorrect
A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336 = 3:4:7 
Question 14 of 50
14. Question
22004 – 29303 + 101299 – 59532 = ?
Correct
22004 – 29303 + 101299 – 59532
123303 – 888.35 = 34468 = 34500Incorrect
22004 – 29303 + 101299 – 59532
123303 – 888.35 = 34468 = 34500 
Question 15 of 50
15. Question
The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
Correct
1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6^{th} number = 11.5Incorrect
1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6^{th} number = 11.5 
Question 16 of 50
16. Question
The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?
Correct
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
i.e., (120/100 * 7x) and (110/100 * 8x)
i.e., 42x/5 and 44x/5
Required ratio = 42x/5 : 44x/5 = 21:22Incorrect
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
i.e., (120/100 * 7x) and (110/100 * 8x)
i.e., 42x/5 and 44x/5
Required ratio = 42x/5 : 44x/5 = 21:22 
Question 17 of 50
17. Question
The greatest number of five digits which is divisible by 32, 36, 40, 42 and 48 is:
Correct
LCM = 10080
10080) 99999 (8
90720
———
9279
99999 – 9279 = 90720Incorrect
LCM = 10080
10080) 99999 (8
90720
———
9279
99999 – 9279 = 90720 
Question 18 of 50
18. Question
If 30% of a number exceeds 20% of it by 18, then find the number?
Correct
Let the number be x.
30% of x = 30/100 * x = 3x/10
20% of x = 20/100 * x = x/5 = 2x/10.
Given that 3x/10 – 2x/10 = 18 => x = 180.
Required number is 180.Incorrect
Let the number be x.
30% of x = 30/100 * x = 3x/10
20% of x = 20/100 * x = x/5 = 2x/10.
Given that 3x/10 – 2x/10 = 18 => x = 180.
Required number is 180. 
Question 19 of 50
19. Question
The ratio of two natural numbers is 5:6. If a certain number is added to both the numbers, the ratio becomes 7:8. If the larger number exceeds the smaller number by 10, find the number added?
Correct
Let the two numbers be 5x and 6x.
Let the number added to both so that their ratio becomes 7:8 be k.
(5x + k)/(6x + k) = 7/8
42x = 7k => k = 2x.
6x – 5x = 10 => x = 10
k = 2x = 20.Incorrect
Let the two numbers be 5x and 6x.
Let the number added to both so that their ratio becomes 7:8 be k.
(5x + k)/(6x + k) = 7/8
42x = 7k => k = 2x.
6x – 5x = 10 => x = 10
k = 2x = 20. 
Question 20 of 50
20. Question
25% of 30% of 45% is equal to?
Correct
(25/100) * (30/100) * (45/100)
1/4 * 3/10 * 9/20
27/800 = 0.03375Incorrect
(25/100) * (30/100) * (45/100)
1/4 * 3/10 * 9/20
27/800 = 0.03375 
Question 21 of 50
21. Question
A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
Correct
D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 minsIncorrect
D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins 
Question 22 of 50
22. Question
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Correct
C’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24
A’s wages : B’s wages : C’s wages
1/6 : 1/8 : 1/24 = 4:3:1
C’s share = 1/8 * 3200 = Rs. 400Incorrect
C’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24
A’s wages : B’s wages : C’s wages
1/6 : 1/8 : 1/24 = 4:3:1
C’s share = 1/8 * 3200 = Rs. 400 
Question 23 of 50
23. Question
Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer)
Correct
CI = 14800{ [ 1 + 13.5/100]^{2} – 1 }
= 14800 { [1 + 27/200]^{2} – 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266Incorrect
CI = 14800{ [ 1 + 13.5/100]^{2} – 1 }
= 14800 { [1 + 27/200]^{2} – 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266 
Question 24 of 50
24. Question
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Correct
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days.Incorrect
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days. 
Question 25 of 50
25. Question
The sides of a cube are in the ratio 1:2 the ratio of their volume is?
Correct
Incorrect

Question 26 of 50
26. Question
A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
Correct
l * 30 = 1200 → l = 40
40 + 30 + 50 = 120
120 * 10 = 1200Incorrect
l * 30 = 1200 → l = 40
40 + 30 + 50 = 120
120 * 10 = 1200 
Question 27 of 50
27. Question
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
Correct
Ratio of times taken by A and B = 100:130 = 10:13
Suppose B takes x days to do the work.
x = (23 * 13)/10 = 299/10
A’s 1 day work = 1/23; B’s 1 day work = 10/299
(A + B)’s 1 day work = (1/23 + 10/299) = 1/13
A and B together can complete the job in 13 days.Incorrect
Ratio of times taken by A and B = 100:130 = 10:13
Suppose B takes x days to do the work.
x = (23 * 13)/10 = 299/10
A’s 1 day work = 1/23; B’s 1 day work = 10/299
(A + B)’s 1 day work = (1/23 + 10/299) = 1/13
A and B together can complete the job in 13 days. 
Question 28 of 50
28. Question
Find the one which does not belong to that group ?
Correct
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.
Incorrect
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

Question 29 of 50
29. Question
Find the one which does not belong to that group ?
Correct
41, 43, 47 and 53 are prime numbers, but not 57.
Incorrect
41, 43, 47 and 53 are prime numbers, but not 57.

Question 30 of 50
30. Question
Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
Correct
(10*10)/100 = 1%loss
100 — 99
? — 1980 => Rs.2000Incorrect
(10*10)/100 = 1%loss
100 — 99
? — 1980 => Rs.2000 
Question 31 of 50
31. Question
Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?
Correct
4/18 + (x 7)/27 + x/36 = 1
x = 16 daysIncorrect
4/18 + (x 7)/27 + x/36 = 1
x = 16 days 
Question 32 of 50
32. Question
A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
Correct
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm —— 100 gm
1000 gm —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.Incorrect
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm —— 100 gm
1000 gm —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams. 
Question 33 of 50
33. Question
A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?
Correct
1/8 – 1/x = 1/10
x = 40Incorrect
1/8 – 1/x = 1/10
x = 40 
Question 34 of 50
34. Question
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Correct
Relative speed of the thief and policeman = 11 – 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 200 – 100 = 100 m.Incorrect
Relative speed of the thief and policeman = 11 – 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 200 – 100 = 100 m. 
Question 35 of 50
35. Question
Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?
Correct
Let the pipe B be closed after x minutes.
30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16
=> x = 14/16 * 24 = 21.Incorrect
Let the pipe B be closed after x minutes.
30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16
=> x = 14/16 * 24 = 21. 
Question 36 of 50
36. Question
In an office, totally there are 6400 employees and 65% of the total employees are males. 25% of the males in the office are atleast 50 years old. Find the number of males aged below 50 years?
Correct
Number of male employees = 6400 * 65/100 = 4160
Required number of male employees who are less than 50 years old = 4160 * (100 – 25)%
= 4160 * 75/100 = 3120.Incorrect
Number of male employees = 6400 * 65/100 = 4160
Required number of male employees who are less than 50 years old = 4160 * (100 – 25)%
= 4160 * 75/100 = 3120. 
Question 37 of 50
37. Question
[(3.572)^{3} + (2.428)^{3}] / [(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}] is equal to .
Correct
[(3.572)^{3} + (2.428)^{3}] / [(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}]
= {(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}}{3.752 + 2.428} / [(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}]
= 3.752 + 2.428 = 6Incorrect
[(3.572)^{3} + (2.428)^{3}] / [(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}]
= {(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}}{3.752 + 2.428} / [(3.572)^{2} – (3.572) * (2.428) + (2.428)^{2}]
= 3.752 + 2.428 = 6 
Question 38 of 50
38. Question
Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?
Correct
Incorrect

Question 39 of 50
39. Question
Simplify : 1 – {1 + (a^{2} – 1)^{1}}^{1}
Correct
1 – {1 + (a^{2} – 1)^{1}}^{1} = 1 – {1 + 1/a^{2} – 1}^{1} = 1 – {a^{2} / a^{2} – 1}^{1} = 1 – (a^{2} – 1)/a^{2} = 1/a^{2}.
Incorrect
1 – {1 + (a^{2} – 1)^{1}}^{1} = 1 – {1 + 1/a^{2} – 1}^{1} = 1 – {a^{2} / a^{2} – 1}^{1} = 1 – (a^{2} – 1)/a^{2} = 1/a^{2}.

Question 40 of 50
40. Question
40 is subtracted from 60% of a number, the result is 50. Find the number?
Correct
(60/100) * X – 40 = 50
6X = 900
X = 150Incorrect
(60/100) * X – 40 = 50
6X = 900
X = 150 
Question 41 of 50
41. Question
Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
Correct
4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120Incorrect
4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120 
Question 42 of 50
42. Question
The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is:
Correct
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500Incorrect
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500 
Question 43 of 50
43. Question
How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?
Correct
50/100 * x = 30 * 20 => x = 1200
Incorrect
50/100 * x = 30 * 20 => x = 1200

Question 44 of 50
44. Question
The ratio between the school ages of Neelam and Shaan is 5:6 respectively. If the ratio between the onethird age of Neelam and half of Shaan’s age of 5:9, then what is the school age of Shaan?
Correct
Let the school ages of Neelam and Shaan be 5x and 6x years respectively.
Then, (1/3 * 5x)/(1/2 * 6x) = 5/9
15 = 15
Thus, Shaan’s age cannot be determined.Incorrect
Let the school ages of Neelam and Shaan be 5x and 6x years respectively.
Then, (1/3 * 5x)/(1/2 * 6x) = 5/9
15 = 15
Thus, Shaan’s age cannot be determined. 
Question 45 of 50
45. Question
The ratio of the cost price and the selling price is 4:5. The profit percent is:
Correct
Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x – 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%.Incorrect
Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x – 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%. 
Question 46 of 50
46. Question
Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
Correct
P(at least one graduate) = 1 – P(no graduates) =
1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6Incorrect
P(at least one graduate) = 1 – P(no graduates) =
1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6 
Question 47 of 50
47. Question
The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Correct
100 * 100 = 10000
125 * 80 = 10000
No changeIncorrect
100 * 100 = 10000
125 * 80 = 10000
No change 
Question 48 of 50
48. Question
A certain number when divided by 45 leaves a remainder 31, what is the remainder if the same number be divided by 15?
Correct
45 + 31 = 76/15 = 1 (Remainder)
Incorrect
45 + 31 = 76/15 = 1 (Remainder)

Question 49 of 50
49. Question
If x = √8 – √7, y = √6 – √5 and z = √10 – 3, which of the following is true?
Correct
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 – √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y.Incorrect
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 – √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y. 
Question 50 of 50
50. Question
Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
Correct
1/20 + 1/30 – 1/40 = 7/120
120/7 = 17 1/7Incorrect
1/20 + 1/30 – 1/40 = 7/120
120/7 = 17 1/7