RRB SSE Online Test Series 1  RRB Mock Test Series 1
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RRB SSE Online Test Series 1  RRB Mock Test Series 1, Online Preparation: RRB Senior Section Engineer, Junior Engineer, NonTechnical Exam Free Online Test Series. Free RRB Online Test for various competitive examination, entrance examination and campus interview. check out Online mock test series for RRB Senior Section Engineer. RRB Online Test for All Subjects, RRB SSE Free Mock Test Series in English. RRB SSE Free Mock Test Series 1. RRB SSE English Language Online Test in English Series 1st. RRB SSE Quantitative Aptitude Quiz 2024, RRB SSE Reasoning Ability Free Online Test. Take RRB SSE Online Quiz. The RRB SSE Full online mock test paper is free for all students. RRB SSE Question and Answers in English and Hindi Series 1. Here we are providing RRB SSE Full Mock Test Paper in English. RRB SSE Mock Test Series 1st 2024. Now Test your self for RRB SSE Exam by using below quiz…
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 Answered
 Review

Question 1 of 50
1. Question
How many numbers up to 500 are divisible by 23?
Correct
500/23 = 21 17/23 => 21 Numbers
Incorrect
500/23 = 21 17/23 => 21 Numbers

Question 2 of 50
2. Question
Find the one which does not belong to that group ?
Correct
The sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.
Incorrect
The sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.

Question 3 of 50
3. Question
If x = √196 + √200, then x/2 + 2/x is?
Correct
x = 14 + 10√2
x/2 = 7 + 5√2
2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7
x/2 + 2/x = 10√2 = 2√50Incorrect
x = 14 + 10√2
x/2 = 7 + 5√2
2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7
x/2 + 2/x = 10√2 = 2√50 
Question 4 of 50
4. Question
A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
Correct
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 – x)2
4.5 + x = 9 2x
3x = 4.5
x = 1.5Incorrect
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 – x)2
4.5 + x = 9 2x
3x = 4.5
x = 1.5 
Question 5 of 50
5. Question
Divide Rs.32000 in the ratio 3:5?
Correct
3/8 * 32000 = 12000
5/8 * 32000 = 20000Incorrect
3/8 * 32000 = 12000
5/8 * 32000 = 20000 
Question 6 of 50
6. Question
A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A’s income is increased by Rs.200 when the rate to profit rises from 5 to 7 percent. Find the Capital of B?
Correct
A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 200
B capital = 15000*1/6 = 2500Incorrect
A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 200
B capital = 15000*1/6 = 2500 
Question 7 of 50
7. Question
If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?
Correct
Speed Ratio = 1:3/4 = 4:3
Time Ratio = 3:4
1 ——– 1/3
3 ——— ? è 1 hourIncorrect
Speed Ratio = 1:3/4 = 4:3
Time Ratio = 3:4
1 ——– 1/3
3 ——— ? è 1 hour 
Question 8 of 50
8. Question
If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers.
Correct
H.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.
Incorrect
H.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.

Question 9 of 50
9. Question
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
Correct
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.Incorrect
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. 
Question 10 of 50
10. Question
Find the one which does not belong to that group ?
Correct
Except Japanian, all others are appropriate usage of citizenship.
Incorrect
Except Japanian, all others are appropriate usage of citizenship.

Question 11 of 50
11. Question
How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
Correct
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
Incorrect
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

Question 12 of 50
12. Question
P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to onethird of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
Correct
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.Incorrect
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together. 
Question 13 of 50
13. Question
Simplify: y^{p(q – r)} . y^{q(r – p)} . y^{r(p – q)}
Correct
y^{p(q – r)} . y^{q(r – p)} . y^{r(p – q)}
= y^{pq – pr + qr – qp + rp – rq}
= y^{p0} = 1.Incorrect
y^{p(q – r)} . y^{q(r – p)} . y^{r(p – q)}
= y^{pq – pr + qr – qp + rp – rq}
= y^{p0} = 1. 
Question 14 of 50
14. Question
A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Correct
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.Incorrect
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m. 
Question 15 of 50
15. Question
A tank 3 m long, 2 m wide and 1.5 m deep is dug in a field 20 m long and 14 m wide. If the earth dug out is evenly spread out over the field, the level of the field will raise by nearly?
Correct
Incorrect

Question 16 of 50
16. Question
106 * 106 – 94 * 94 = ?
Correct
106 * 106 – 94 * 94 = (106)^{2} – (94)^{2}
= (106 + 94)(106 – 94) = (200 * 12) = 2400Incorrect
106 * 106 – 94 * 94 = (106)^{2} – (94)^{2}
= (106 + 94)(106 – 94) = (200 * 12) = 2400 
Question 17 of 50
17. Question
In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Correct
Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 – 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3Incorrect
Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 – 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3 
Question 18 of 50
18. Question
3251 + 587 + 369 – ? = 3007
Correct
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200Incorrect
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200 
Question 19 of 50
19. Question
3 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?
Correct
3M = 6W — 20 days
12M + 8W —–?
24W + 8 W = 32W —?
6W — 20 32 —–?
6 * 20 = 32 * x => x = 15/4 daysIncorrect
3M = 6W — 20 days
12M + 8W —–?
24W + 8 W = 32W —?
6W — 20 32 —–?
6 * 20 = 32 * x => x = 15/4 days 
Question 20 of 50
20. Question
A certain sum becomes Rs. 20720 in four years and 24080 in six years at simple interest. Find sum and rate of interest?
Correct
Let the interest for one year be x.
As amount = Principal + Interest, we have
P + 4x = 20720 — (1) ; P + 6x = 24080 — (2)
Solving the equations (1) and (2), we can get
P = Rs. 14000 and x = Rs. 1680
Interest for one year on Rs. 14000 is Rs. 1680
So, R = (100 * 1680)/(14000 * 1) = 12% p.a.Incorrect
Let the interest for one year be x.
As amount = Principal + Interest, we have
P + 4x = 20720 — (1) ; P + 6x = 24080 — (2)
Solving the equations (1) and (2), we can get
P = Rs. 14000 and x = Rs. 1680
Interest for one year on Rs. 14000 is Rs. 1680
So, R = (100 * 1680)/(14000 * 1) = 12% p.a. 
Question 21 of 50
21. Question
If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are?
Correct
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750Incorrect
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750 
Question 22 of 50
22. Question
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
Correct
Required probability = 1 – 1/126 = 125/126
Incorrect
Required probability = 1 – 1/126 = 125/126

Question 23 of 50
23. Question
On dividing 2272 as well as 875 by 3digit number N, we get the same remainder. The sum of the digits of N is:
Correct
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10.Incorrect
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10. 
Question 24 of 50
24. Question
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
Correct
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6^{th} = 294 + 312 – 550 = 56Incorrect
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6^{th} = 294 + 312 – 550 = 56 
Question 25 of 50
25. Question
20% of 40 + ? % of 80 = 120
Correct
20% of 40 + ? % of 80 = 120
=> 800/100 + ?/100 * 80 = 120
=> ? = 140Incorrect
20% of 40 + ? % of 80 = 120
=> 800/100 + ?/100 * 80 = 120
=> ? = 140 
Question 26 of 50
26. Question
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
Correct
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35Incorrect
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35 
Question 27 of 50
27. Question
Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Correct
x + y = 80
x – 4y = 5
x = 65 y = 15Incorrect
x + y = 80
x – 4y = 5
x = 65 y = 15 
Question 28 of 50
28. Question
The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?
Correct
Let the prices of X, Y and Z be 8k, 5k and 3k respectively.
After increase
Price of X = 8k * 125/100 = 10k
Price of Y = 5k * 120/100 = 6k
Price of Z = 3k * (133 1/3)/100 = 4k
Required ratio = 10k : 6k : 4k = 5 : 3 : 2.Incorrect
Let the prices of X, Y and Z be 8k, 5k and 3k respectively.
After increase
Price of X = 8k * 125/100 = 10k
Price of Y = 5k * 120/100 = 6k
Price of Z = 3k * (133 1/3)/100 = 4k
Required ratio = 10k : 6k : 4k = 5 : 3 : 2. 
Question 29 of 50
29. Question
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Correct
Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 mIncorrect
Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m 
Question 30 of 50
30. Question
Two cars P and Q start at the same time from A and B which are 120 km apart. If the two cars travel in opposite directions, they meet after one hour and if they travel in same direction (from A towards B), then P meets Q after 6 hours. What is the speed of car P?
Correct
Let their speed be x km/hr and y km/he respectively.
Then, 120/(x + y) = 1 => x + y = 120 — (i)
Now, when they move in same direction:
(Distance traveled by P in 6 hrs) – (Distance traveled by Q in 6 hrs) = 120 km
6x – 6y = 120 => x – y = 20 — (ii)
Sloving (i) and (ii), we get x = 70, y = 50
P’s speed = 70 km/hr.Incorrect
Let their speed be x km/hr and y km/he respectively.
Then, 120/(x + y) = 1 => x + y = 120 — (i)
Now, when they move in same direction:
(Distance traveled by P in 6 hrs) – (Distance traveled by Q in 6 hrs) = 120 km
6x – 6y = 120 => x – y = 20 — (ii)
Sloving (i) and (ii), we get x = 70, y = 50
P’s speed = 70 km/hr. 
Question 31 of 50
31. Question
The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Correct
S = 4
M = x
DS = x + 4
US = x – 4
6/(x + 4) + 6/(x – 4) = 2
x = 8Incorrect
S = 4
M = x
DS = x + 4
US = x – 4
6/(x + 4) + 6/(x – 4) = 2
x = 8 
Question 32 of 50
32. Question
26.98% of 6002 + 45.01% of 4199 = ?
Correct
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500Incorrect
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500 
Question 33 of 50
33. Question
A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
Correct
(x – 5)/15 + x/20 = 1
x = 11 3/7 daysIncorrect
(x – 5)/15 + x/20 = 1
x = 11 3/7 days 
Question 34 of 50
34. Question
A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
Correct
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000Incorrect
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000 
Question 35 of 50
35. Question
A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?
Correct
Incorrect

Question 36 of 50
36. Question
Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.
Correct
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.Incorrect
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours. 
Question 37 of 50
37. Question
The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?
Correct
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
i.e., (120/100 * 7x) and (110/100 * 8x)
i.e., 42x/5 and 44x/5
Required ratio = 42x/5 : 44x/5 = 21:22Incorrect
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
i.e., (120/100 * 7x) and (110/100 * 8x)
i.e., 42x/5 and 44x/5
Required ratio = 42x/5 : 44x/5 = 21:22 
Question 38 of 50
38. Question
6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = ?
Correct
6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = 20/3 * 48/5 * 7/3 + 4/3
= 448/3 + 4/3 = 452/3 = 150 2/3Incorrect
6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = 20/3 * 48/5 * 7/3 + 4/3
= 448/3 + 4/3 = 452/3 = 150 2/3 
Question 39 of 50
39. Question
Find the one which does not belong to that group ?
Correct
Except Real, all others are rhyming words.
Incorrect
Except Real, all others are rhyming words.

Question 40 of 50
40. Question
In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
Correct
Time taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.
Time taken by A = 200 – 10 = 190 sec.Incorrect
Time taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.
Time taken by A = 200 – 10 = 190 sec. 
Question 41 of 50
41. Question
The area of sector of a circle whose radius is 12 metro and whose angle at the center is 42° is?
Correct
42/360 * 22/7 * 12 * 12 = 52.8 m^{2}
Incorrect
42/360 * 22/7 * 12 * 12 = 52.8 m^{2}

Question 42 of 50
42. Question
A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
Correct
US = 25
DS = 35
M = (35 + 25)/2 = 30Incorrect
US = 25
DS = 35
M = (35 + 25)/2 = 30 
Question 43 of 50
43. Question
How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Correct
Speed of train relative to man = 63 – 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.Incorrect
Speed of train relative to man = 63 – 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec. 
Question 44 of 50
44. Question
A can do a piece of work in 10 days and B can do it in 15 days and C can do it 20 days. They started the work together and A leaves after 2 days and B leaves after 4 days from the beginning. How long will work lost?
Correct
2/10 + 4/15 + x/20 = 1
x = 32/3 = 10 2/3Incorrect
2/10 + 4/15 + x/20 = 1
x = 32/3 = 10 2/3 
Question 45 of 50
45. Question
A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:
Correct
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12%Incorrect
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12% 
Question 46 of 50
46. Question
Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?
Correct
1120 = P [1 + (5*12/5)/100]
P= 1000Incorrect
1120 = P [1 + (5*12/5)/100]
P= 1000 
Question 47 of 50
47. Question
The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?
Correct
one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days.Incorrect
one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days. 
Question 48 of 50
48. Question
Dacid obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Correct
Average = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.
Incorrect
Average = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

Question 49 of 50
49. Question
The areas of the two spheres are in the ratio 1: 4. The ratio of their volume is?
Correct
4πr_{1}^{2} : 4πr_{2}^{2} = 1 : 4
r_{1} : r_{2 }= 1 : 2
4/3 πr_{1}^{3 }: 4/3 πr_{2}^{3}
r_{1}^{3} : r_{2}^{3} = 1 : 8Incorrect
4πr_{1}^{2} : 4πr_{2}^{2} = 1 : 4
r_{1} : r_{2 }= 1 : 2
4/3 πr_{1}^{3 }: 4/3 πr_{2}^{3}
r_{1}^{3} : r_{2}^{3} = 1 : 8 
Question 50 of 50
50. Question
Twofifth of onethird of threeseventh of a number is 15. What is 40% of that number?
Correct
Let the number be x. Then,
2/5 of 1/3 of 3/7 of
x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2
40% of 525/2 = (40/100 * 525/2) = 105Incorrect
Let the number be x. Then,
2/5 of 1/3 of 3/7 of
x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2
40% of 525/2 = (40/100 * 525/2) = 105